5^x+1=4^2x-1

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Solution for 5^x+1=4^2x-1 equation: 



5^x+1=4^2x-1

We move all terms to the left:

5^x+1-(4^2x-1)=0

We get rid of parentheses

5^x-4^2x+1+1=0

We add all the numbers together, and all the variables

5^x-4^2x+2=0

We move all terms containing x to the left, all other terms to the right

5^x-4^2x=-2

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